使用u-boot_2016_01启动mini2440（二）uboot内存分布

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启动内存的分布主要是在board_init_f内划分的:

按照我的代码，分布如下：

代码log:

U-Boot 2016.01-g3401853-dirty (Apr 04 2016 - 08:06:26 -0400)

U-Boot code: 33A00000 -> 33A7BEF4 BSS: -> 33ACAAE4

CPUID: 32440001

FCLK: 405.600 MHz

HCLK: 101.400 MHz

PCLK: 50.700 MHz

DRAM: Monitor len: 000CAAE4

Ram size: 04000000

Ram top: 34000000

TLB table from 33ff0000 to 33ff4000

LCD panel info: 320 x 240, 32 bit/pix

Reserving 300k for LCD Framebuffer at: 33fa5000

Reserving 810k for U-Boot at: 33eda000

Reserving 4096k for malloc() at: 33ada000

Reserving 80 Bytes for Board Info at: 33ad9fb0

Reserving 168 Bytes for Global Data at: 33ad9f08

RAM Configuration:

Bank #0: 30000000

DRAM: 64 MiB

New Stack Pointer is: 33ad9ee0

Relocation Offset is: 004da000

Relocating to 33eda000, new gd at 33ad9f08, sp at 33ad9ee0

WARNING: Caches not enabled

Flash: 0 Bytes

NAND: 256 MiB

MMC: S3C MMC: 0

In: serial

Out: serial

Err: serial

Net: dm9000

MINI2440 #

MINI2440 # bdinfo

arch_number = 0x000007CF

boot_params = 0x30000100

DRAM bank = 0x00000000

-> start = 0x30000000

-> size = 0x04000000

eth0name = dm9000

ethaddr = 08:00:3e:26:0a:5b

current eth = dm9000

ip_addr = 192.168.1.10

baudrate = 115200 bps

TLB addr = 0x33FF0000

relocaddr = 0x33EDA000

reloc off = 0x004DA000

irq_sp = 0x33AD9EF0

sp start = 0x33AD9EE0

FB base = 0x33FA5000

MINI2440 #

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